How to display uploader without form builder

emergingdzns - 1 month ago

I'm building a module with severals streams. I need to display a form on the front end of the site. This one form is going to post data to various streams (depending on input). Those streams include some file field types and some files field types.

But I can't figure out how to display the field type on the front end without using the form builder.

If it's not possible, how to do I handle the uploading on my controller?

jcastillotx - 1 month ago

So you need to be able to send data based on conditions to other streams ??

emergingdzns - 1 month ago

Sort of. I have a stream called "registration". There are 3 sub-types of registrations, each with it's own stream because each sub-type has different data fields. So building my form, I have it setup using javascript to show the fields for each sub-type depending on the one chosen. So, when the data is submitted it includes the registration stream data and the data for the sub-type chosen. Two of the sub types have a file field type and one has a files field type.

So in my form I have basic file selectors and submitting to my controller. In the controller I have the following (with a LOT stripped out to simplify the example):

use Request;
public function receiveData(Request $request) {
                if ($request->file('form_field_name')) {
                    if ($upload_file = $uploader->upload($request->file('form_field_name'), $folders->find('named_folder'))) {

Just trying to get a handle on how to have the system automatically handle the file in a way that makes more sense than how I'm doing it above. Seems like I ought to be able to say use Request; ... public function receiveData(Request $request) { if ($request->file('form_field_name')) { if ($upload_file = $uploader->upload($request->file('form_field_name'), $folders->find('named_folder'))) { print_r($upload_file->getAttributes()); } } } or something like this and have it know to take the file I named and deal with the upload data and add it to the records based on the stream configuration.

piterden - 1 month ago

     * Accepts the information of the uploaded file as provided by the PHP global $_FILES.
     * The file object is only created when the uploaded file is valid (i.e. when the
     * isValid() method returns true). Otherwise the only methods that could be called
     * on an UploadedFile instance are:
     *   * getClientOriginalName,
     *   * getClientMimeType,
     *   * isValid,
     *   * getError.
     * Calling any other method on an non-valid instance will cause an unpredictable result.
     * @param string      $path         The full temporary path to the file
     * @param string      $originalName The original file name
     * @param string|null $mimeType     The type of the file as provided by PHP; null defaults to application/octet-stream
     * @param int|null    $size         The file size
     * @param int|null    $error        The error constant of the upload (one of PHP's UPLOAD_ERR_XXX constants); null defaults to UPLOAD_ERR_OK
     * @param bool        $test         Whether the test mode is active
     * @throws FileException         If file_uploads is disabled
     * @throws FileNotFoundException If the file does not exist
                    $uploaded = new UploadedFile(

                    $file = $this->uploader->upload($uploaded, $folder);

emergingdzns - 1 month ago

Thanks. I have that already. My point is, that the stream that has the files field type has another table that's associated because on that stream the user can upload multiple files. It seems strange that with all the intelligence built into P3 that there's no simply one-line that I could write that would make it take all the files uploaded, put them where they need to go, associate them to the files module AND also add the record of those files to the stream that I'm working with. Instead it looks like I'm going to have to create a model for that sub-table that has just the relationship for the files to the stream. Maybe there is a way to do it but it isn't documented anywhere. There's documentation on how to DISPLY files AFTER they are uploaded, but nothing about the actual uploading/relationship process.

ryanthompson - 1 month ago

I would start with obtaining the field type from the field type collection and start building it up with whatever it needs to operate. Off the top of my head idk but $useMe = $fieldTypes->get('files'); or file or whatever. Then see what breaks and keep adding information to it until it doesn't break lol

emergingdzns - 1 month ago

Ok I made a break through in a sort of "duh" moment. I've got it able to upload the file, get the ids and assign the id to the stream. However, I have one more question about this. I need to be able to create a folder dynamically, if it doesn't already exist, either for the user or for the specific "registration" object. I have it now doing this to get the top level folder:

$folder = $folders->findBySlug('works');

But I would like to then add a sub-folder inside of the 'works' folder. So for registration id $folder = $folders->findBySlug('works'); I would like a folder inside of 3456 called works. How do I do this. I've been digging through the files module looking for clues as to how to add the folder but I'm just not seeing it. Can someone point me in the right direction there?